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Home » This Super Hero Squad Switching ON—Win Big or Die Trying! - Red Crowns

This Super Hero Squad Switching ON—Win Big or Die Trying! - Red Crowns

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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\( I(4) = I(3) + I(2) + I(1) = 4 + 2 + 1 = 7 \equiv 0 \mod 7 \)
\( I(5) = I(4) + I(3) + I(2) = 0 + 4 + 2 = 6 \mod 7 \)
\( I(6) = I(5) + I(4) + I(3) = 6 + 0 + 4 = 10 \equiv 3 \mod 7 \)
\( I(7) = I(6) + I(5) + I(4) = 3 + 6 + 0 = 9 \equiv 2 \mod 7 \)
\( I(8) = I(7) + I(6) + I(5) = 2 + 3 + 6 = 11 \equiv 4 \mod 7 \)
\( I(9) = I(8) + I(7) + I(6) = 4 + 2 + 3 = 9 \equiv 2 \mod 7 \)
\( I(10) = I(9) + I(8) + I(7) = 2 + 4 + 2 = 8 \equiv 1 \mod 7 \)
Thus, the remainder when \( I(10) \) is divided by 7 is \( oxed{1} \)...
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Solution: The sum of the first \( n \) cubes is given by the formula:

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